Some interesting math could come out of the west this year
If Cal and Sask lose there last two games all three contending teams will be 11 and 7
Cal will have won the season series with Sask and lost the season series to Win. However Sask won the season series against Win. Cal would be ahead of Sask but behind Win, but Win would be behind Sask. So who would finish where.
I know it’s not likely for Sask and Cal to lose out but what happens if they do.
This was discussed on another website. The CFL has not clarified if tiebreakers reset once they are used.
Two sources have given two separate results that are different.
In true CFL fashion, we have no idea.
Rock Paper Scissors
Lol
Under that unlikely scenario (all 3 with 11-7 records), I’d suggest that they look at their Home/Away records:
Stamps 7-2 Home, 4-5 Away
Riders 7-2 Home, 4-5 Away
Bombers 8-1 Home, 3-6 Away
If the Home record is given more weight, then Bombers would be 1st, Stamps 2nd, and Riders 3rd.
If Away is considered to be more important, then Bombers end up in 3rd, Stamps 1st and Riders 2nd.
Of course, it’s highly likely Stamps will beat the Lions (unless BLM is out), and/or highly likely that Riders will win at least one vs Esks, so a 3-way tie is not really in the cards.
Here you go. You figure it out. But I think it would be points for and against among the three teams.
When two or more member Clubs are tied in the final Division standings at the conclusion of the regular season schedule, preferential ranking for playoff purposes shall be determined on the basis of the following descending-order priorities and shall be awarded to the Club that:
a) has won the greater number of games played against all member Clubs of the League, then b) has the higher winning percentage in all games played against all of the other tied Club(s), then c) has scored the higher net aggregate of points (i.e. points scored for less points scored against) in all games played against all of the other tied Club(s), then d) has scored the higher net quotient of points (i.e. points scored for divided by points scored against) in all games played against all of the other tied Club(s), then e) has the higher winning percentage in all games played against all member Clubs of the Division, then f) has scored the higher net aggregate of points in games played against all member Clubs of the Division, then g) has scored the higher quotient of points in games played against all member Clubs of the Division, then h) has scored the higher net aggregate of points in games played against all member Clubs of the League, then i) has scored the higher net quotient of points in games played against all member Clubs of the League, then j) has won a coin toss against the other tied Club.
Note: If two Clubs remain tied after other Club(s) are eliminated during any step, tie breaker reverts to step a).
Point differential is interesting but it’s not a very appealing measure, because of the impact of an occasional blow-out game. However, it was interesting to look at the numbers so far.
Overall, Cats, at 192, are light years above all the rest!!! The next closest are Bombers at 98. Also, none of the other 3 Eastern teams have positive points (even the Als are at -4)! In the West, only the Lions are negative: Bombers 98, Riders 88, Stamps 71, Esks 19, Lions -36.
b) has the higher winning percentage in all games played against all of the other tied Club(s)
Cal 3 of 5 60%
Win 3 of 6 50%
Sask 2 of 5 40%
This is all way too complex.
I say, they should just look at their record against the cats, # 1 team in the league.
Sask
Calgary
Winnipeg
Done!
(When there is no clear cut logical answer - just make it up ?)
There you go. I hadn’t realized that Winnipeg had played an extra game against the two others.
I don’t really like b) very much because it’s unbalanced in the number of games played among the 3 top teams.
CAL plays WPG 3x and SSK 2x, SSK plays WPG 3x and CAL 2x; therefore, WPG plays both SSK and CAL 3x.
It would be ideal if each team had to play each other team in their division 3x (a total of 12 games for each team in the division), but of course, that would mess up the home-and-home schedule versus the East division teams (where 8 games would be needed).
With 2 weeks remaining, the way I see it, CAL and SSK could, each, still finish first, second, or third.
WPG can only finish either second or third.
Keeps things exciting. Looking forward to these final weeks of the regular season.
If they all tried their best, followed the rules and no one got hurt, in a sense, aren’t they all winners ?
Its better the West fight while we sit back on easy street don’t matter will see one of them Nov 24th
Well, in a sense yes, but not in every sense.
This is by far my favourite post today :D:D:D
That’s why they use percentages for this. Seems reasonable to me.
Yes, I’m very aware of that, except the “base” (i.e. denominator) is different for one of the 3 teams (i.e. Winnipeg) in the triplet, so it’s not really a “fair” comparison. Comparing percentages can be deceiving, especially when the base differences get larger. Of course, here the difference is only 1 (6 vs. 5).
However, comparing each team’s win percentage within the division would be fairer; since all teams in that division play 10 games within their division, you wouldn’t need to use percentages in the first place.
He's back!
Cats will deactivate him by Nov. 17th, if he is not already enjoying the offseason by the week before. 