# interesting last day scenerio

Not sure I have ever seen where with just two games left to go in a cfl season, there are six possible combinations for one semi final game.

very interesting ending to a strange year.

Would one of our Tie-Breaker geniuses be so kind as to run through the various scenarios?

think all that who would win what had been done in other threads.

the bottom line is we could have either mont, tor, or ham host either bc or sask. that make 6 possibilities. That's is pretty unusual at this point.

I try to simply all the discussion

ham loses, tor hosts
ham win <8 ham hosts
ham win >7 mon hosts

don't feel like getting into the possibilities with ties. probably wont be any anyhow.

3*2=6

I think you have your less than and greater than symbols backwards, but otherwise that sums it up.

oops :oops: I shouldn't post before I have had my morning pepsi

wait a minute, actually I am right. Its about who hosts the east semi

What if Hamilton wins by 7? Why does Montreal get first? Their series would be tied.

I hear that mont wins the tiebreaker, not sure why, could be division record.

Yes, the series would be tied.
That's why the point differential of 7 is significant.

Yes I understand that but based on the next tie breaker which from my understanding tho can be wrong is season total points for minus points against. Hamilton is plus 8 Montreal is minus 20.

When two or more member Clubs are tied in the final Division standings at the conclusion of the regular season schedule, preferential ranking for playoff purposes shall be determined on the basis of the following descending-order priorities and shall be awarded to the Club that:

1. has won the greater number of games played against all member Clubs of the League, then,
2. has the higher winning percentage in all games played against all of the other tied Club(s), then,
3. has scored the higher net aggregate of points (i.e. points scored for less points scored against) in all games played against all of the other tied Club(s), then,
4. has scored the higher net quotient of points (i.e. points scored for divided by points scored against) in all games played against all of the other tied Club(s), then,
5. has the higher winning percentage in all games played against all member Clubs of the Division, then,
6. has scored the higher net aggregate of points in games played against all member Clubs of the Division, then,
7. has scored the higher quotient of points in games played against all member Clubs of the Division, then,
8. has scored the higher net aggregate of points in games played against all member Clubs of the League, then,
9. has scored the higher net quotient of points in games played against all member Clubs of the League, then,
10. has won a coin toss against the other tied Club.

Note: If two Clubs remain tied after other Club(s) are eliminated during any step, tie breaker reverts to step a).

if ham wins by 7, since there are only 2 teams tied, then that will eliminate the first 4 leaving number 5 as the tiebreaker

Thanks

I predict that there will be a 9-9 team, in the Grey Cup. 8)

naah, either a 10-9 or 11-9 from the east

:cowboy:
:D

Can't wait for next week's playoff games. Should be interesting.