Nice. So a four way tie for 2nd in the West and all four tied with the top two Eastern teams.
To determine the order of finish in the West, the rules say, after looking at total number of wins, to look at the games among the tied clubs.
“has the higher winning percentage in all games played against all of the other tied Club(s)”
The head-to-head-to-head-to-head among the 9-9 teams BC, CGY, EDM, and WPG would be, I think,
- BC 4-3 57.1%
- CGY 4-4 50.0%
- EDM 4-4 50.0%
- WPG 3-4 42.9%
BC gets 2nd in the West and hosts the Western semi-final
The h2h2h among the remaining CGY, EDM, WPG would be:
- CGY 4-2 66.7%
- EDM 3-2 60.0%
- WPG 1-4 20.0%
CGY gets 3rd and travels to BC for the Western semi.
The h2h between EDM and WPG would have each team 1-1 as WPG won 36-23 on June 26 and we are assuming EDM wins on October 11.
After h2h record in the tiebreaker rules is points in h2h games:
“has scored the higher net aggregate of points (i.e. points scored for less points scored against) in all games played against all of the other tied Club(s)”
If EDM wins by more than 13 points they go east for the Eastern semi and WPG misses the playoffs in spite of being tied for first in the East and second in the West.
If EDM wins by fewer that 13, the roles are reversed.
If EDM wins by exactly 13 in your scenario, then we go deeper into the tie-breaker rules.